Finding the circumference of a triangle with given base and height?

[Nelson108]

The base of the triangle is 3, and the length is 5, giving it an area of 7.50.

How do I calculate the circumference? The answer here says it is 13.83 but I don't understand how it got to that conclusion. Any help would be very appreciated.

 

[Harry_the_cat]

The base of the triangle is 3, and the length is 5, giving it an area of 7.50.

How do I calculate the circumference? The answer here says it is 13.83 but I don't understand how it got to that conclusion. Any help would be very appreciated.

If it is a right angled triangle, then use Pythagoras' rule to find the hypotenuse. Then add the three sides together to get the perimeter.

(BTW The word circumference is used for the perimeter of a circle.)

 

[Nelson108]

If it is a right angled triangle, then use Pythagoras' rule to find the hypotenuse. Then add the three sides together to get the perimeter.

(BTW The word circumference is used for the perimeter of a circle.)

I appreciate the response, but here is where i'm confused. If I square the base(9) and square the height(25) I get 34 as the hypotenuse, but if I add 34 to 5 and 3 I clearly don't get 13.83 for my code's output.

 

[Nelson108]

To get 13.83 as perimeter, then triangle HAS TO BE a right triangle.
Did you post the EXACT original problem?

Thing is in my coding assignment instructions, it doesn't specify what type of triangle it is. It simply asks for the circumference of the triangle whatever it may be. I assume it is a right triangle, but I frankly don't understand how it is 13.83 even using the Pythagorean theorem.

 

[Deleted member 4993]

I appreciate the response, but here is where i'm confused. If I square the base(9) and square the height(25) I get 34 as the hypotenuse - INCORRECT, but if I add 34 to 5 and 3 I clearly don't get 13.83 for my code's output.

√(32 + 52) = √(9 + 25) = √(34) = 5.830952 ← hypotenuse