finding the domain: f(x) = x/x-3, g(x) = -1/x

[bailey07]

f(x) =x/x-3 ; g(x) =-1/x

..i got {xIxdoes not =3

in f(x) you can't have 3 as x in the denominator..thats how i got my answer..

am i right?

 

[masters]

Re: finding the domain

You are right. And, in your g(x) equation, the domain is all real numbers except 0.

 

[stapel]

..i got {xIxdoes not =3 am i right?

Assuming that f(x) is actually x/(x - 3), and assuming that the instructions (not included) were to "find the domain of f(x)", then yes, in set notation the answer would be "{x | x is real and x is not equal to 3}".

But if you meant something else or if the instructions asked for something else, then the above may be incorrect. :shock:

Eliz.