Finding the domain of an equation

[Guest]

Hi I need help finding the domain of this equation

y=2sin 2(x-pi/4)

I got everything asked for except for the domain.the ans. is suppose to be DOMAIN: 0<orequal to X < or equal to pi

but I don't get it cuz don't you have to move to the right pi/4 as well? Like the period ends at 2pi for sin, then you compress horizontally by 1/2 which gives you pi, then don't you have to move right pi/4 so then the domain shouldn't be less than pi??

I'm confused on the graphing of this.
-Anna

 

[Guest]

Is there any more information given? You can take the sine of any number, so 2(x - pi/4) can be anything, so x can be anything.