Probability
Full Member
- Joined
- Jan 26, 2012
- Messages
- 432
I am not sure if I am posting in the right thread, I am not sure if this is a geometry, calculus or algebra type of problem?
OK I am working on a circle problem, I have found the gradient of a straight line which is - 2/3
I have found the midpoints of this line, which are [4/2, - 2/2]
I am asked to find from this the equation of the perpendicular bisector AB
I am struggling to understand two things;
1) Using y - y1 = m(x - x1)
If y - (- 2/2 ) = - 2/3 x - 4/2
and then I bring over the the RHS ( - 2/2) which then becomes (2/2) as the denominators are already the same, i.e.
y = -2/3 x - 4/2 - 2/2
y = - 2/3x - 6/2
At this point the denominators are now different which can't be right?
If I do this, - 2/3 - 6/2 = - 18/6 + 4/6 = - 14/6 = - 7/3
So my equation looks like;
y = - 7/3x
Which I am quite confident is incorrect.
If y = - 7/3 (4/2) = - 4.67
I am not convinced.
OK I am working on a circle problem, I have found the gradient of a straight line which is - 2/3
I have found the midpoints of this line, which are [4/2, - 2/2]
I am asked to find from this the equation of the perpendicular bisector AB
I am struggling to understand two things;
1) Using y - y1 = m(x - x1)
If y - (- 2/2 ) = - 2/3 x - 4/2
and then I bring over the the RHS ( - 2/2) which then becomes (2/2) as the denominators are already the same, i.e.
y = -2/3 x - 4/2 - 2/2
y = - 2/3x - 6/2
At this point the denominators are now different which can't be right?
If I do this, - 2/3 - 6/2 = - 18/6 + 4/6 = - 14/6 = - 7/3
So my equation looks like;
y = - 7/3x
Which I am quite confident is incorrect.
If y = - 7/3 (4/2) = - 4.67
I am not convinced.