I have 3 triangles.
C ........................E.....................H
/I....................... /I...................../I
/.I......................./.I.................../.I
/..I....................../..I................../..I
/...I.height=10....... /...I height=x....../...I height=100
/....I.................../....I .............../....I
/.....I................../.....I.............../.....I
/63 90I................/63 90I............../63 90I
A--------B .............D--------F...........G-------J
x 6
I know that a triangle has a total degree of 180. So if 63+90=153 then the third angle must be 27 degrees.
Here's what my homework says...
Find the length of the leg opposite the 63º angle. (#'s 1,4,7)
Find the length of the leg adjacent to the 63º angle. (#'s 2,5,8)
Find the trigonometric ratio and the decimal equivalent for tan 63º. (#'s 3,6,9)
Round all decimal answers to the hundredths place. For problems 3, 6 and 9, you will have two answers.
1.10(right?) 4.help? 7.100(right?)
2.help? 5.6(right?) 8.help?
3.* 6.* 9.*
*I don't know what the trigonometric ratio means. The decimal equivalent mean like 1/2 = .5 , And a ratio is usually a fracton....
So I'm assuming 3, 6, & 9 are going to be ratio's of a number somewhere above.
My proffesor has been no help.
He just sits in the front of the room & gives us our assignment & deadline & won't answer any questions.
He says that we must learn from our mistakes. I've tried that theory... but because of my "mistakes" I now have a 62% in the class. Will you help me figure out how to solve this problem & other problems like this in the future?
C ........................E.....................H
/I....................... /I...................../I
/.I......................./.I.................../.I
/..I....................../..I................../..I
/...I.height=10....... /...I height=x....../...I height=100
/....I.................../....I .............../....I
/.....I................../.....I.............../.....I
/63 90I................/63 90I............../63 90I
A--------B .............D--------F...........G-------J
x 6
I know that a triangle has a total degree of 180. So if 63+90=153 then the third angle must be 27 degrees.
Here's what my homework says...
Find the length of the leg opposite the 63º angle. (#'s 1,4,7)
Find the length of the leg adjacent to the 63º angle. (#'s 2,5,8)
Find the trigonometric ratio and the decimal equivalent for tan 63º. (#'s 3,6,9)
Round all decimal answers to the hundredths place. For problems 3, 6 and 9, you will have two answers.
1.10(right?) 4.help? 7.100(right?)
2.help? 5.6(right?) 8.help?
3.* 6.* 9.*
*I don't know what the trigonometric ratio means. The decimal equivalent mean like 1/2 = .5 , And a ratio is usually a fracton....
So I'm assuming 3, 6, & 9 are going to be ratio's of a number somewhere above.
My proffesor has been no help.
He just sits in the front of the room & gives us our assignment & deadline & won't answer any questions.
He says that we must learn from our mistakes. I've tried that theory... but because of my "mistakes" I now have a 62% in the class. Will you help me figure out how to solve this problem & other problems like this in the future?