S Shogun New member Joined Apr 23, 2006 Messages 18 Apr 23, 2006 #1 In a triangle CDE, CD =3y, DE=30, and CE=45. Determine the range of possible values for y. 45-30=15 3y=CD=75 3y=CD=3 3y = 15 3y = 3 y =5 y =25 Did I do this correctly? How do I write my answer correctly?
In a triangle CDE, CD =3y, DE=30, and CE=45. Determine the range of possible values for y. 45-30=15 3y=CD=75 3y=CD=3 3y = 15 3y = 3 y =5 y =25 Did I do this correctly? How do I write my answer correctly?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Apr 23, 2006 #2 the sum of any two sides of a triangle must be greater than the 3rd side ... 30 + 45 > 3y 3y + 45 > 30 3y + 30 > 45 solving each inequality for y ... y < 25 y > -5 y > 5 now, using the most restrictive conditions yields 5 < y < 25
the sum of any two sides of a triangle must be greater than the 3rd side ... 30 + 45 > 3y 3y + 45 > 30 3y + 30 > 45 solving each inequality for y ... y < 25 y > -5 y > 5 now, using the most restrictive conditions yields 5 < y < 25
