Finding the x-intercept?

[jonboy]

Is there a way to figure this out w/out graphing? I know how to find the y-intercept, but how would I find the x-intercept?

 

[galactus]

Set y=0 and solve for x.

\(\displaystyle 2x-(0)+8=0\)

2x=-8

x=-4

 

[jonboy]

Set y=0 and solve for x.

\(\displaystyle 2x-(0)+8=0\)

2x=-8

x=-4

I thought the x denotes slope not the x-intercept?

 

[jonboy]

I guess the number in front of the x must be slope. But how come the y-intercept is b and not y in the form y=mx+b?

 

[galactus]

The b is is the y-intercept in the form y=mx+b.

You said you knew how to find the y-intercept, set x=0.

You do the same for the x-intercept, set y=0.

Your slope-intercept form is y=2x+8

It crosses the x axis at x=-4. -8+8=0.

I think, jonboy, you're thinking to hard about this. Relax. It'll be OK. :wink:

 

[jonboy]

I think, jonboy, you're thinking to hard about this. Relax. It'll be OK.

LOL yeah your right WOW I feel better already. *Thank you* Galactus I knew you would not leave me hanging.