The Preacher
Junior Member
- Joined
- Sep 13, 2005
- Messages
- 53
The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.
I'd be able to find the other side, then the area... but it involves a square root thing. My mind inexplicably locks up when I see one. I can't get past it.
Here's what I've got so far:
Use the Pythagorean Theorem to find b.
6 x 6 = 36 --- \(\displaystyle c^2\)=36
2 x 2 = 4 --- \(\displaystyle a^2\)=4
36-4=32 --- \(\displaystyle c^2-a^2=32\)
Now I just have to find out what 32 is the square of, but I can't. Also, from looking at the problem, the answer is going to be in radical form, so I probably won't know what to do afterward either.
Sorry to be so useless about math... at least I can use TeXaide. Thanks guys.
-The Preacher
I'd be able to find the other side, then the area... but it involves a square root thing. My mind inexplicably locks up when I see one. I can't get past it.
Here's what I've got so far:
Use the Pythagorean Theorem to find b.
6 x 6 = 36 --- \(\displaystyle c^2\)=36
2 x 2 = 4 --- \(\displaystyle a^2\)=4
36-4=32 --- \(\displaystyle c^2-a^2=32\)
Now I just have to find out what 32 is the square of, but I can't. Also, from looking at the problem, the answer is going to be in radical form, so I probably won't know what to do afterward either.
Sorry to be so useless about math... at least I can use TeXaide. Thanks guys.
-The Preacher