Finding x and y from equations X= 5% (182.04 - Y), Y = 5% (182.04- X )

Holmes

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X= 5% (182.04 - Y)
Y = 5% (182.04- X )

Please show step by step process

I tried to substitute equation X in to' X ' of equation Y but im stuck afterward
 
X= 5% (182.04 - Y)
Y = 5% (182.04- X )

Please show step by step process

I tried to substitute equation X in to' X ' of equation Y but im stuck afterward

Okay, that's a great first step! So that leaves you with:

Y = 0.05(182.04 - [0.05(182.04 - Y)])

I think a good next step would be to start working from the inside out, and distribute the multiplication. If you did that, you'd have:

Y = 0.05(182.04 - [9.102 - 0.05Y])

Where does this lead you? What do you think you'd do next? As a hint, recall that subtracting a negative is the same as adding.
 
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X= 5% (182.04 - Y)
Y = 5% (182.04- X )

Please show step by step process

I tried to substitute equation X in to' X ' of equation Y but im stuck afterward
Please reply showing what you did (all the steps) and where you ended up. Thank you! ;)
 
Please reply showing what you did (all the steps) and where you ended up. Thank you! ;)

Y=.05(182.04-(.05(182.04-Y)))
Y=.05(182.04-(9.102-.05Y))
Y=9.102-(.4551-.0025Y)
Y=9.102-.4551+.0025Y
Y=8.6469+.0025Y
.9975Y=8.6469
Y=8.6686
Thank you for the hint !!!
 
Y=.05(182.04-(.05(182.04-Y)))
Y=.05(182.04-(9.102-.05Y))
Y=9.102-(.4551-.0025Y)
Y=9.102-.4551+.0025Y
Y=8.6469+.0025Y
.9975Y=8.6469
Y=8.6686
Thank you for the hint !!!

Yes, that's correct. Good job! The only minor note I'd make is that the value you've given is just an approximation of the actual value of Y. In most cases that's fine, although your instructor may prefer an exact (fractional) answer. If you do end up leaving it as a decimal approximation, you'll probably want to note it as such (i.e. write \(\displaystyle Y \approx 8.6686\)). Additionally, depending on the full text of the problem, you may want to use the value of Y you found to solve for the value of X as well.
 
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