G gnozahs New member Joined Oct 22, 2009 Messages 6 Oct 22, 2009 #1 What is the x coordinate of the absolute minimum of 6x + [12/x] when x > 0? I'm not sure how to derive the equation.
What is the x coordinate of the absolute minimum of 6x + [12/x] when x > 0? I'm not sure how to derive the equation.
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Oct 22, 2009 #2 Have you tried \(\displaystyle x=1.5\)? How about finding the minimum of \(\displaystyle 6x + 12/x\)?
Have you tried \(\displaystyle x=1.5\)? How about finding the minimum of \(\displaystyle 6x + 12/x\)?
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Oct 22, 2009 #3 \(\displaystyle f(x) \ = \ 6x+\frac{12}{x}, \ find \ its \ derivative \ and \ set \ it \ to \ zero.\)
\(\displaystyle f(x) \ = \ 6x+\frac{12}{x}, \ find \ its \ derivative \ and \ set \ it \ to \ zero.\)
