Finite math: R(x) = 28x, C(x) = -15 + 344; break-even pt is?

[stephnj1]

A revenue function is R(x) = 28x and a cost function is C(x) = -15 + 344. The break-even point is:

a. (224, 11)
b. (8, 224)
c. (15, 420)
d. (26.5, 741)

 

[stapel]

Re: Finite math: R(x) = 28x, C(x) = -15 + 344; break-even pt

A revenue function is R(x) = 28x and a cost function is C(x) = -15 + 344. The break-even point is....

There is a typo in your "cost" function, I think. Shouldn't there be a variable?

Meanwhile, the break-even point is the point at which costs equal revenues. So set the functions equal and solve.

If you get stuck, please reply showing your steps and reasoning. Thank you.

Eliz.