(x+1)dy - (y+1)dx = (x+1)Sqrt(y+1)dx From Tenenbaum - Pollard ODE
V volkan New member Joined Oct 22, 2016 Messages 3 Oct 22, 2016 #1 (x+1)dy - (y+1)dx = (x+1)Sqrt(y+1)dx From Tenenbaum - Pollard ODE
D Deleted member 4993 Guest Oct 22, 2016 #2 volkan said: (x+1)dy - (y+1)dx = (x+1)Sqrt(y+1)dx From Tenenbaum - Pollard ODE Click to expand... let: U = x + 1 → dx = dU V = √(y+1) → dV = 1/2 * dy/√(y+1) → dy = 2 * V * dV Continue....
volkan said: (x+1)dy - (y+1)dx = (x+1)Sqrt(y+1)dx From Tenenbaum - Pollard ODE Click to expand... let: U = x + 1 → dx = dU V = √(y+1) → dV = 1/2 * dy/√(y+1) → dy = 2 * V * dV Continue....
V volkan New member Joined Oct 22, 2016 Messages 3 Oct 22, 2016 #3 Subhotosh Khan said: let: U = x + 1 → dx = dU V = √(y+1) → dV = 1/2 * dy/√(y+1) → dy = 2 * V * dV Continue.... Click to expand... thank you sir
Subhotosh Khan said: let: U = x + 1 → dx = dU V = √(y+1) → dV = 1/2 * dy/√(y+1) → dy = 2 * V * dV Continue.... Click to expand... thank you sir
