I am doing some practice problems, and cannot figure this one out.
Let f(x) = c/(1+x^2)
For what value of c is f a pdf?
I understand that in order for it to be a probability density function, it's integral from a to b must equal one, and I know that the answer is 1/pi, but I have no idea how to solve for c.
Thanks in advance for any help.
Let f(x) = c/(1+x^2)
For what value of c is f a pdf?
I understand that in order for it to be a probability density function, it's integral from a to b must equal one, and I know that the answer is 1/pi, but I have no idea how to solve for c.
Thanks in advance for any help.