A Angela123 Junior Member Joined Oct 9, 2008 Messages 54 Nov 12, 2008 #1 For what numbers a and b is the system of equations below satisfied by x=b and y=a? x-3y =a 7x+3y =62 I have no idea how to solve this, except for if I was to cancel out the y's and then I'd have 8x=a+62, but then what?
For what numbers a and b is the system of equations below satisfied by x=b and y=a? x-3y =a 7x+3y =62 I have no idea how to solve this, except for if I was to cancel out the y's and then I'd have 8x=a+62, but then what?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Nov 12, 2008 #2 Angela123 said: For what numbers a and b is the system of equations below satisfied by x=b and y=a? x-3y =a 7x+3y =62 Click to expand... Since y = a, then the system is actually: . . . . .1x - 3y = 1y . . . . .7x + 3y = 62 ...which adds down to give: . . . . .8x = y + 62 As one would expect with a system of two equations in three variables, there is an infinite number of solutions. Eliz.
Angela123 said: For what numbers a and b is the system of equations below satisfied by x=b and y=a? x-3y =a 7x+3y =62 Click to expand... Since y = a, then the system is actually: . . . . .1x - 3y = 1y . . . . .7x + 3y = 62 ...which adds down to give: . . . . .8x = y + 62 As one would expect with a system of two equations in three variables, there is an infinite number of solutions. Eliz.