4(1−√3)=4−4√3
I still do not understand how to do the distributive property to get the 4(1−√3).
For example this is what i can come up with, with my current understanding:
4-4√3
2*2-2*2√3 / 2
2-4√3
-2√3
[MATH]4[/MATH] and [MATH]4\sqrt{3}[/MATH] are not like terms and cannot be combined as you did in post #4
think about [MATH]4-4x[/MATH], where [MATH]x[/MATH] represents [MATH]\sqrt{3}[/MATH] ... both terms have [MATH]4[/MATH] as a common factor
[MATH]4 \cdot 1 - 4 \cdot x = 4(1 - x)[/MATH]
One of your problems is that you do not use parentheses properlyTry this question:
10 -√75 / 5
10 - √25√3 / 5
10 - 5√3 / 5 ----> Where do i take it from here?
The answer should be 2 - √3
One of your problems is that you do not use parentheses properly
[MATH]\dfrac{4 - \sqrt{48}}{4} = (4 - \sqrt{48})/4[/MATH]
[MATH]\dfrac{4 - \sqrt{16 * 3}}{4} = (4 - \sqrt{16 * 3})/4[/MATH]
[MATH]\dfrac{4 - 4\sqrt{3}}{4} = (4 - 4 \sqrt{3})/4[/MATH]
[MATH]\dfrac{4(1 - \sqrt{3})}{4} = 4(1 - \sqrt{3})/4[/MATH]
[MATH]1 - \sqrt{3} = 1 - \sqrt{3}[/MATH]
You have the same problem with parentheses in your latest problem.