function transformations

actresschanel

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Jul 13, 2021
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For function transformations, isf(5(x-20) like (5x-100) so moved right by 100 and compressed horizontally by 5??

Like if there's f(x-2) and you have to horizontally stretch by 2, you do (1/2x-2) instead of 1/2(x-2) right?

and for domain and range for the new transformed function, you apply what you would to a point?

Tysm
 
What you have said is correct.

We know the effect on the graph when we make the following simple substitutions:

[MATH]\hspace20ex x \mapsto x+k \hspace2ex[/MATH] (translation -k in x-direction)
[MATH]\hspace20ex x \mapsto ax \hspace2ex[/MATH] ('stretch' by [MATH]\tfrac{1}{a}[/MATH] in x-direction)

If we want to know what effect a complex transformation will have on a graph, we should carry out the complex transformation by a sequence of these simple substitutions, which we know how to interpret.

E.g. starting with the graph of [MATH]f(x)[/MATH], we want to know what the graph of [MATH]f(5x-100)[/MATH] looks like. We carry out the complex transformation [MATH]x \mapsto 5x-100[/MATH] by a sequence of the simple substitutions: [MATH]\hspace3ex [/MATH]x is replaced by [MATH](x+k)[/MATH][MATH]\hspace45ex[/MATH] and x is replaced by [MATH]ax[/MATH]
1626167297743.png
In your next example, you are starting with the function [MATH]f(x-2)[/MATH] and you would like to know what function will have the same graph stretched [MATH]\times2[/MATH] in the [MATH]x[/MATH]-direction.
We know the simple substitution [MATH]x \mapsto \tfrac{1}{2}x[/MATH] will produce a function which has this graph.
So the function will be [MATH]f \left(\tfrac{1}{2}x-2\right)[/MATH]1626167622032.png

What would the graph of [MATH]f \left(\tfrac{1}{2}(x-2)\right)[/MATH] look like, compared to the graph of [MATH]f(x-2)[/MATH]?
Consider the complex transformation as a sequence of the simple substitutions:
1626168034393.png
 
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