fundamental trigonometric identities

[flakine]

Write the first in terms of the second:

tan(t)/cos(t), sin(t)

 

[happy]

tan(t)/cos(t), sin(t)

sin
-------------- * cos= what?
cos

 

[flakine]

=sin, but how are you setting this up?

what am I doing wrong (sin/cos)/cos =sin/cos^2???

 

[happy]

Doesn't tan= sin/cos?

division (a/b)/b

= a
-------*b = a, not a/b^2
b

 

[Unco]

=sin, but how are you setting this up?

what am I doing wrong (sin/cos)/cos =sin/cos^2???

You are correct, well done.

 

[flakine]

The correct answer is:

sin/(1-sin^2)

 

[Unco]

cos^2(x) + sin^2(x) = 1

so
cos^2(x) = 1 - sin^2(x)

 

[flakine]

So true, thanks!