no1moparnut
New member
- Joined
- Feb 18, 2009
- Messages
- 1
Find the general solution to t^2 y' = 9 - y^2
y = 2( 1 + Ce -4/t ) / ( 1 - Ce -4/t )
y = 2( 1 + Ce 4/t ) / ( 1 - Ce 4/t )
y = 3( 1 + Ce -6/t ) / ( 1 - Ce -6/t )
y = 3( 1 + Ce 6/t ) / ( 1 - Ce 6/t )
y = 4( 1 + Ce -8/t ) / ( 1 - Ce -8/t )
y = 4( 1 + Ce 8/t ) / ( 1 - Ce 8/t )
y = 5( 1 + Ce -10/t ) / ( 1 - Ce -10/t )
y = 5( 1 + Ce 10/t ) / ( 1 - Ce 10/t )
None of these.
y = 2( 1 + Ce -4/t ) / ( 1 - Ce -4/t )
y = 2( 1 + Ce 4/t ) / ( 1 - Ce 4/t )
y = 3( 1 + Ce -6/t ) / ( 1 - Ce -6/t )
y = 3( 1 + Ce 6/t ) / ( 1 - Ce 6/t )
y = 4( 1 + Ce -8/t ) / ( 1 - Ce -8/t )
y = 4( 1 + Ce 8/t ) / ( 1 - Ce 8/t )
y = 5( 1 + Ce -10/t ) / ( 1 - Ce -10/t )
y = 5( 1 + Ce 10/t ) / ( 1 - Ce 10/t )
None of these.