vampirewitchreine
Junior Member
- Joined
- Aug 2, 2011
- Messages
- 82
(This was in an old section: Conditions for Special Parallelograms)
Two common crafts in Japan are paper-folding (origami) and paper-cutting (kirigami). Since both crafts usually require a square sheet of paper, it is helpful to know how to cut a nonsquare rectangular sheet of paper into a square.
Step 1: Fold the paper so that a short edge lines up with a long edge.
Step 2: Then cut along the edge of the two-layer triangle.
Why is the resulting rectangle a square? Which theorem does this process illustrate?
My theorems:
Ways to prove that a Parallelogram is a Rectangle
Ways to prove that a Parallelogram is a Rhombus
I did this a couple of ways.I did this with a piece of paper and a math program that I have downloaded. Perhaps I'm over thinking this or perhaps overlooking something totally obvious, but I'd greatly appreciate any help that you can give me here.)
The following is what I did on my program (The colors were only to help know what happened..... the dark blue color is the extra rectangle that gets cut off and the purple/pink is the square, with the 2 colors showing that it was folded into two congruent triangles to make it into a square):

Two common crafts in Japan are paper-folding (origami) and paper-cutting (kirigami). Since both crafts usually require a square sheet of paper, it is helpful to know how to cut a nonsquare rectangular sheet of paper into a square.
Step 1: Fold the paper so that a short edge lines up with a long edge.
Step 2: Then cut along the edge of the two-layer triangle.
Why is the resulting rectangle a square? Which theorem does this process illustrate?
My theorems:
Ways to prove that a Parallelogram is a Rectangle
- If the diagonals of a parallelogram are congruent, then it is a rectangle
- If one angle of a parallelogram is a right angle, then it is a rectangle
Ways to prove that a Parallelogram is a Rhombus
- If the diagonals of a parallelogram are perpendicular, then it is a rhombus
- If two consecutive sides of a parallelogram are congruent, then it is a rhombus
I did this a couple of ways.I did this with a piece of paper and a math program that I have downloaded. Perhaps I'm over thinking this or perhaps overlooking something totally obvious, but I'd greatly appreciate any help that you can give me here.)
The following is what I did on my program (The colors were only to help know what happened..... the dark blue color is the extra rectangle that gets cut off and the purple/pink is the square, with the 2 colors showing that it was folded into two congruent triangles to make it into a square):
