Okay here's the question...
Write a 2-column proof.
Given: AB=DC; AD=BC; AF=CE
Prove: segment DE is parallel to segment BF
(hint first prove triangle ABC is congruent to triangle CDA. use this fact to show angle 1 and angle 2 are congruent. then prove the other 2 triangles are congruent.)
Here's the picture: (I COULN'T MAKE A LINE FROM A TO C-SO THAT IS A DIAGONAL LINE AND THEN FROM B TO F- THERE IS A DIAGONAL LINE TOO...BOTH LINE AC AND LINE BF TOUCH EACH OTHER....INADDITION FROM D TO E THERE IS A LINE AND ALSO TOUCHES LINE AC)
Code:
A ------------------- B
/ 1 /
/ /
/ F /
/ E /
/ 2 /
D ------------------ C
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