Given f(x) = ax3 - 3x and point (-2, 0) on graph, find....
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Re: Look at my question..I think its right forum,soz if its
Do you mean this?
f(x) = ax<SUP>3</SUP> - 3x
If so, then here's how you would proceed. Since you know that (-2, 0) lies on the graph of f(x), then f(x) = 0 when x = -2. Substitute:
0 = a*(-2)<SUP>3</SUP> - 3(-2)
0 = -8a + 6
8a = 6
a = 3/4
If I have misinterpreted your problem, please repost, clarifiying exactly what you meant.
jojo said:I think this is the right forum, probably wrong but oh well
f(x)=ax3-3x. The point (-2,0) lies on the graph of y=f(x). Find the value of a.
thanks xxJoJoxx
Do you mean this?
f(x) = ax<SUP>3</SUP> - 3x
If so, then here's how you would proceed. Since you know that (-2, 0) lies on the graph of f(x), then f(x) = 0 when x = -2. Substitute:
0 = a*(-2)<SUP>3</SUP> - 3(-2)
0 = -8a + 6
8a = 6
a = 3/4
If I have misinterpreted your problem, please repost, clarifiying exactly what you meant.