gradient: K^1/2 + 2L^1/2 = Q

[__SB]

Hoping somebody could help me please.
K^1/2 + 2L^1/2 = Q
K = (Q – 2L^1/2)^2
dK/dL = 2(Q – 2L^1/2) * (0 – L^-1/2) = -2(Q – 2L^1/2) /L^1/2
dK/dL should equal : -2 * (K/L)^1/2
Q is a constant, K is on the y axis and L on the X axis
Where does Q go?

 

[__SB]

Can’t see how to delete thread… solved it – just substituteQ in at end.

 

[Deleted member 4993]

Hoping somebody could help me please.
K^1/2 + 2L^1/2 = Q
K = (Q – 2L^1/2)^2
dK/dL = 2(Q – 2L^1/2) * (0 – L^-1/2) = -2(Q – 2L^1/2) /L^1/2
dK/dL should equal : -2 * (K/L)^1/2
Q is a constant, K is on the y axis and L on the X axis
Where does Q go?

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