Graph the line

[AAA]

Is there an easy way to graph an equation like this (Y=3/4s-1) instead of having to choose random numbers and evaluating them, because sometimes the numbers come out big and the graph they gave me has numbers until 10 only.

 

[Harry_the_cat]

This is in y=mx+c form. Do you know what m and c give you?

 

[AAA]

c is the y intercept. but I don't know the others

 

[Harry_the_cat]

Yes c is the y-intercept. And m is the gradient.
The first thing you can do is plot the y-intercept of -1 on your graph.
Then from that point, interpret the gradient of 3/4 as rise/run. So, from the point (0,-1) where do you get to if you run 4 units (in the pos x direction) and then rise 3 units (in the pos y direction). What point do you end up at?

 

[Harry_the_cat]

Did you find it?

 

[AAA]

Is it (4,4)?

 

[Harry_the_cat]

No. Start at (0, -1). Move 4 units right and 3 units up.

 

[AAA]

Hi! Sorry for mot responding earlier is my answer correct

 

[Harry_the_cat]

Yes very good. I'd add arrows at each end of your line to indicate it keeps on going indefinitely.

So the method to graph lines in the form = = mx + c is:

• plot the y-intercept
• interpret the gradient as rise/run (note: eg m = 3 = 3/1 and if it's negative then it will be a fall rather than a rise)

 

[AAA]

Sure! Thank you so so much!

 

[AAA]

?

 

[AAA]

One question pls. How do I now when its rise and when its run?

 

[skeeter]

slope = [imath]m = \dfrac{rise}{run}[/imath]

 

[Harry_the_cat]

What Skeeter said! That's the definition of gradient (slope). Rise is the numerator (on the top).

 

[mmm4444bot]

How do I [know] when [it's] rise and when [it's] run?

The change in x is called the 'run', and the change in y is called the 'rise'.

The ratio (change in y)/(change in x) is called the slope (it's a measure of the line's "steepness").

Are you taking a math class, AAA?

[imath]\;[/imath]

 

[AAA]

thank you mmm4444bot! Yeah I'm taking Intermediate Algebra and in Geometry in the same time ?​