S sclang63 New member Joined Sep 17, 2008 Messages 2 Sep 17, 2008 #1 the instructions are simply, "graph the equation". I'm trying to manipulate this equation into a form that makes that possible. y=4/(2x+1)
the instructions are simply, "graph the equation". I'm trying to manipulate this equation into a form that makes that possible. y=4/(2x+1)
D Deleted member 4993 Guest Sep 17, 2008 #2 Re: graphing an equation sclang63 said: the instructions are simply, "graph the equation". I'm trying to manipulate this equation into a form that makes that possible. y=4/(2x+1) Click to expand... Why do you think it is not possible in the present form? Do you know what yould the graph of \(\displaystyle y \, = \, \frac{1}{x}\) look like. The given function is just transformed (x-y shift & contraction/expansion) of the above. Another way: First find assymptotes, roots, maxima, minima, inflection point, etc. of the given function. Then just make chart according to the domain and ranges that you have found above.
Re: graphing an equation sclang63 said: the instructions are simply, "graph the equation". I'm trying to manipulate this equation into a form that makes that possible. y=4/(2x+1) Click to expand... Why do you think it is not possible in the present form? Do you know what yould the graph of \(\displaystyle y \, = \, \frac{1}{x}\) look like. The given function is just transformed (x-y shift & contraction/expansion) of the above. Another way: First find assymptotes, roots, maxima, minima, inflection point, etc. of the given function. Then just make chart according to the domain and ranges that you have found above.
S sclang63 New member Joined Sep 17, 2008 Messages 2 Sep 17, 2008 #3 Re: graphing an equation thanks...a little rusty....had a mental block.
