C Connie New member Joined Oct 6, 2006 Messages 14 Dec 12, 2006 #1 I am having trouble understanding problems like the following: Graph y= x^2 - 2x + 1 for -2 <= x <= - 4. How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry?
I am having trouble understanding problems like the following: Graph y= x^2 - 2x + 1 for -2 <= x <= - 4. How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry?
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Dec 13, 2006 #2 Graph y= x^2 - 2x + 1 for -2 <= x <= - 4. How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry? Click to expand... Simply graph the equation as usual (it’s a parabola). Just don’t graph any of the parabola that lies outside your interval. For any quadratic of the form y = ax^2 + bx + c, the equation of the axis of symmetry is x = -b/2a
Graph y= x^2 - 2x + 1 for -2 <= x <= - 4. How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry? Click to expand... Simply graph the equation as usual (it’s a parabola). Just don’t graph any of the parabola that lies outside your interval. For any quadratic of the form y = ax^2 + bx + c, the equation of the axis of symmetry is x = -b/2a
