T tinad New member Joined Jun 4, 2006 Messages 10 Jun 11, 2006 #1 Does the graph f(x)=1+e^x have a horizontal asymptote at y=1? I get that e^x = 0 so you're left with 1. If e^x = 0 then e^0 = 1. Would it have an inflection point at (0,2)?
Does the graph f(x)=1+e^x have a horizontal asymptote at y=1? I get that e^x = 0 so you're left with 1. If e^x = 0 then e^0 = 1. Would it have an inflection point at (0,2)?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Jun 11, 2006 #2 f(x) = 1 + e<sup>x</sup> has a horizontal asymptote at y = 1. it does not have any points of inflection ... f(x) is concave up throughout its entire domain because f"(x) = e<sup>x</sup> > 0 for all x.
f(x) = 1 + e<sup>x</sup> has a horizontal asymptote at y = 1. it does not have any points of inflection ... f(x) is concave up throughout its entire domain because f"(x) = e<sup>x</sup> > 0 for all x.
