Hello! "Find the inverse of f(x)= x^2+x where x is greater than or equal to -1/2"

brooklyngal

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Hello! "Find the inverse of f(x)= x^2+x where x is greater than or equal to -1/2"

I'm studying for a precalculus midterm and i need to find the inverse of the functions. I have the answer to the problem but its the method of solving that's really stumping me. Can anyone help?

the problem is find the inverse of f(x)= x^2+x where x is greater than or equal to -1/2

Thank you!
 
I'm studying for a precalculus midterm and i need to find the inverse of the functions. I have the answer to the problem but its the method of solving that's really stumping me. Can anyone help?

the problem is find the inverse of f(x)= x^2+x where x is greater than or equal to -1/2

Thank you!
Your function is:

y = x^2 + x

First thing you do for "inversion of polynomials is exchange "y" for "x" and vice-versa in the given equation. What do you get?

Then solve for "y" in terms of "x" (using the transformed equation). That is the inverted function.
 
... its the method of solving that's really stumping me.

Find the inverse of f(x)= x^2+x where x is greater than or equal to -1/2
You can use the regular method, as pointed out in the previous reply. The only "special" thing about this is that you'll need the Quadratic Formula. Also, you'll need to use the given restriction to figure out which part of the square root (the "plus" or the "minus" part) you'll need for your inverse function. ;)
 
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