Help / Advice needed on Intergration

Mathmasteriw

Mathmasteriw

Junior Member
Joined
Oct 22, 2020
Messages
85
Hi Everyone ,
Stuck on this ,
Dont know how to get to the next step,..
Any help greatly appreciated as always ?68E6D3AF-76B0-4DE3-966C-70A9D8E7B7D4.jpeg8E8F77B9-5A28-48F4-91E7-E172F38B9711.jpeg
 
[math]q= \dfrac{E}{R} \int_0^1 e^{-kt} \, dt[/math] where [math]k = \dfrac{1}{RC}[/math]
[math]q = \dfrac{E}{R} \bigg[-\dfrac{e^{-kt}}{k} \bigg]_0^1 = EC \bigg[1 - e^{-\frac{1}{RC}} \bigg][/math]
[MATH]q = 10^{-5} \bigg[1 - \dfrac{1}{e} \bigg] [/MATH] Coulombs
 
skeeter said:
[math]q= \dfrac{E}{R} \int_0^1 e^{-kt} \, dt[/math] where [math]k = \dfrac{1}{RC}[/math]
[math]q = \dfrac{E}{R} \bigg[-\dfrac{e^{-kt}}{k} \bigg]_0^1 = EC \bigg[1 - e^{-\frac{1}{RC}} \bigg][/math]
[MATH]q = 10^{-5} \bigg[1 - \dfrac{1}{e} \bigg] [/MATH] Coulombs
Click to expand...
Hi Skeeter,
Thank you so much for your reply & help!
Where dose that fit into my work? Dose that continue from my last line?
thank again Skeeter !
 
Mathmasteriw said:
Hi Skeeter,
Thank you so much for your reply & help!
Where dose that fit into my work? Dose that continue from my last line?
thank again Skeeter !
Click to expand...
You made a mistake in the line before last line of your work (while evaluating integrand at the limits). Otherwise you & skeeter agree.
 
I see you use then 'k' in the equation.
What is the 'k'?
sorry if its a stupid question but I'm just a little confused.
:) thank you
 
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