HELP! ASAP!!

[sjmaddox]

Yes:

[MATH]f(x)=2x^3-15x^2+22x+15[/MATH]
You could factor, or use division knowing two of the zeroes.

-1/2 is the other zero?

 

[Steven G]

Try to see if it works!
Is \(\displaystyle 2(\frac{-1}{2})^3 - 15(\frac{-1}{2})^2+ 22(\frac{-1}{2}) +15 =0?\)

 

[Steven G]

Yes, x is one of the values. And X is because it is an inequality. So it is apart of the "therefore" statement (x is an element of...)

I was extremely desperate and did not expect an answer in all honesty. This is how the question is worded on my page. I would be extremely thankful if you were able to help!

Please understand that x and X are not the same. You wrote (x is an element of...), using x and not X. Just write xE(3,5). Also there is no inequality!

I must admit that I did not think xE(3,5), f(x)<0 meant xE(3,5) when f(x)<0 which is my problem, not yours.

 

[sjmaddox]

-1/2 is the other zero?

Perfect! thank you so much! You're a literal lifesaver