Help math corrections: E and F are INDEPENDENT events...

[KJG2012]

E and F are INDEPENDENT events
P(E) = 1/3
P(E union F) = 1/2
What is p(F)?



I know the answer is 1/4 but how do you come to that conclusion????

 

[tkhunny]

What does INDEPENDENT mean in relation to the compound probability? P(A and B) = ????

 

[KJG2012]

Im not sure I believe it means that B does not depend on A...

 

[pka]

E and F are INDEPENDENT events
P(E) = 1/3
P(E union F) = 1/2
What is p(F)?

You are expected to know that:
\(\displaystyle \mathcal{P}(E\cup E)=\mathcal{P}(E)+\mathcal{P}(F)-\mathcal{P}(E\cap F)\).

Use the Independence to simplify \(\displaystyle \mathcal{P}(E\cap F)\).

Solve for \(\displaystyle \mathcal{P}(F)\).