Help me out. Can you find out correct answers
- Thread starter Zeroz
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D
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Please show us your work behind those two "incorrect" answers - so that you correct your own mistake.
Steven G
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- Dec 30, 2014
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162 = 6th term
162/3 = 5th term
(162/3)/3 = 4th term
[(162/3)/3]/3 = 3rd term
162/3/3/3/3 = 2nd term
162/3/3/3/3/3= 1st term
Or let a = 1st term
3a = 2nd term
3(3a) = 3rd term
3(3(3a)) = 4th term
3(3(3(3a))) = 5th term
3(3(3(3(3a))))= 162 = 6th term
What is the problem?
162/3 = 5th term
(162/3)/3 = 4th term
[(162/3)/3]/3 = 3rd term
162/3/3/3/3 = 2nd term
162/3/3/3/3/3= 1st term
Or let a = 1st term
3a = 2nd term
3(3a) = 3rd term
3(3(3a)) = 4th term
3(3(3(3a))) = 5th term
3(3(3(3(3a))))= 162 = 6th term
What is the problem?
Thanks brother