Because the line \(\displaystyle \overleftrightarrow {XP}\) is a tangent to the circle \(\displaystyle O\) so the the angle tex]m(\algleOPX)=\frac{\pi}{2}[/tex] or a right angle. Now consider \(\displaystyle angle POB\) intercepts an arc of length \(\displaystyle 16\), Can ypu use \(\displaystyle \frac{36}{180^o}=\frac{16}{m(\angle POB)}\) to show that \(\displaystyle m(\angle POB)=80^o\) so \(\displaystyle m(\angle PXB)=10^o\).
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