R Razzle New member Joined Feb 5, 2012 Messages 1 Feb 5, 2012 #1 Solve without negative exponents 3x^-1-y^-2/x^-2+2y^-1 And 7x^-1/x^-3+y^-4
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Feb 5, 2012 #2 Hello, Razzle! Did you really expect us to GUESS what you meant? Solve without negative exponents. . . (a) . 3x^-1-y^-2/x^-2+2y^-1 . . (b) . 7x^-1/x^-3+y^-4 Click to expand... You wrote: .3x^-1-y^-2/x^-2+2y^-1 . . . . . . . . . . . . . . . . . ↑ There is a division . . . but what is divided by what? The way it's written, it would be: .\(\displaystyle 3x^{-1} - \dfrac{y^{-2}}{x^{-2}} + 2y^{-1}\) \(\displaystyle \text{It could be: }\;3x^{-1} - \dfrac{y^{-2}}{x^{-2} + 2y^{-1}}\) . . but that would be typed: .3x{-1} - y^{-2}/(x^{-2} + 2y^{-1}) \(\displaystyle \text{Or it could be: }\;\dfrac{3x^{-1} - y^{-2}}{x^{-2}} + 2y^{-1}\) . . But that would be typed: .(3x^{-1} - y^{-2})/x^{-2} + 2y^{-1} \(\displaystyle \text{Or possibly: }\;\dfrac{3x^{-1} - y^{-2}}{x^{-2} + 2y^{-1}}\) . . But that would be typed: .(3x^{-1} - y^{-2})/(x^{-2} + 2y^{-1})
Hello, Razzle! Did you really expect us to GUESS what you meant? Solve without negative exponents. . . (a) . 3x^-1-y^-2/x^-2+2y^-1 . . (b) . 7x^-1/x^-3+y^-4 Click to expand... You wrote: .3x^-1-y^-2/x^-2+2y^-1 . . . . . . . . . . . . . . . . . ↑ There is a division . . . but what is divided by what? The way it's written, it would be: .\(\displaystyle 3x^{-1} - \dfrac{y^{-2}}{x^{-2}} + 2y^{-1}\) \(\displaystyle \text{It could be: }\;3x^{-1} - \dfrac{y^{-2}}{x^{-2} + 2y^{-1}}\) . . but that would be typed: .3x{-1} - y^{-2}/(x^{-2} + 2y^{-1}) \(\displaystyle \text{Or it could be: }\;\dfrac{3x^{-1} - y^{-2}}{x^{-2}} + 2y^{-1}\) . . But that would be typed: .(3x^{-1} - y^{-2})/x^{-2} + 2y^{-1} \(\displaystyle \text{Or possibly: }\;\dfrac{3x^{-1} - y^{-2}}{x^{-2} + 2y^{-1}}\) . . But that would be typed: .(3x^{-1} - y^{-2})/(x^{-2} + 2y^{-1})
