help on cos^-1 equation
- Thread starter alyren
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- Apr 12, 2005
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Do you mean this?
\(\displaystyle 9\cdot\cos^{-1}(x)-\pi\;=\;7\cdot\cos^{-1}(x)\)
Solve for the inverse cosine of x.
\(\displaystyle \cos^{-1}(x) = \frac{\pi}{2}\)
Use the properties of a function and it's inverse.
\(\displaystyle x = \cos\left(\frac{\pi}{2}\right)\)
Are we there, yet?
\(\displaystyle 9\cdot\cos^{-1}(x)-\pi\;=\;7\cdot\cos^{-1}(x)\)
Solve for the inverse cosine of x.
\(\displaystyle \cos^{-1}(x) = \frac{\pi}{2}\)
Use the properties of a function and it's inverse.
\(\displaystyle x = \cos\left(\frac{\pi}{2}\right)\)
Are we there, yet?