Help On Questions

Cmills

New member
Joined
Nov 8, 2009
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Hello I have two geometry questions and was wondering if anyone can help me.

1. Simplify Completely

x-3.......x+3
___....=_____
x-1.......2x+3

(sorry for the formatting ignore the ...)

2.Find the area and perimeter

The shape looks like this: http://www.karenfayeth.com/trapezoid.jpg

AND is labeled as follows: Top base is 50, bottom base is 92, and left side is 35.


THANKS! Any help is appreciated
 
Cmills said:
Hello I have two geometry questions and was wondering if anyone can help me.

1. Simplify Completely

x-3.......x+3
___....=_____
x-1.......2x+3

(sorry for the formatting ignore the ...)

2.Find the area and perimeter

The shape looks like this: http://www.karenfayeth.com/trapezoid.jpg

AND is labeled as follows: Top base is 50, bottom base is 92, and left side is 35.


THANKS! Any help is appreciated

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.
 
Thats the thing I'm not sure where to start on either of these problems. Sorry and THANKS
 
Are you saying that you can't figure out the perimeter of that trapezoid?

If so, only your teacher can help you...
 
number 1 i have no clue.

Number 2 I know the perimeter but I cant figure out the height of it and in order to find the area i need the height because forumla for area of a trapezoid is a=1/2H(b1+b2)

THANKS
 
1. Simplify Completely

x-3.......x+3
___....=_____
x-1.......2x+3
Write your problem this way:

(x – 3)/(x – 1) = (x + 3)/(2x + 3)

Multiply both sides of the equation by the two denominators and simplify:

(x – 3)(2x + 3) = (x + 3)(x – 1)

Expand and simplify next.
 
2.Find the area and perimeter

The shape looks like this: http://www.karenfayeth.com/trapezoid.jpg

AND is labeled as follows: Top base is 50, bottom base is 92, and left side is 35.

We can only solve this problem if we assume that we have an isosceles trapezoid, i.e., both sides are 35.

Draw vertical lines from the ends of the top base down to the bottom base. You now have two right triangles and enough information to figure out the lengths of the sides. (Hint: Pythagorean Theorem.)
 
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