help on sec^-1

[alyren]

use calculator to find the value

sec^-1(-7/3)

how do i put sec^-1 in calculator?

i try put (1/cos^-1(-7/3)) and getting error domain
am i doing it wrong or there is no solution.

 

[mmm4444bot]

use calculator to find the value sec^-1(-7/3)

how do i put sec^-1 in calculator?

That depends upon the particular calculator that you're using.

When we see a superscript -1 appearing to the right of a function name, the notation does NOT mean an exponent of -1.

It means the inverse function.

For example, if y = f(x), then f[sup:3tdwak39]-1[/sup:3tdwak39](y) = x.

(I hope that you've worked with inverse functions before.)

In other words, sec[sup:3tdwak39]-1[/sup:3tdwak39](-7/3) represents the angle whose secant is -7/3.

Since sec(2.0137) = -7/3, we have:

sec[sup:3tdwak39]-1[/sup:3tdwak39](-7/3) = 2.0137

What calculator do you use ?

 

[alyren]

i using TI 83 plus,
i also find a new way to solve it, i don't know if its right or not,

sec^-1(-7/3)
sec^-1(-7/3)= data
=> sec data =-7/3
cos data=-3/7
data =cos^-1(-3/7)
(by using calculator) data =2.02

 

[mmm4444bot]

Yes, that works.

But your value 2.02 is not properly rounded.

Rounding to 2 decimal places, we have 2.01.