T tmac324 New member Joined Sep 29, 2009 Messages 9 Sep 29, 2009 #1 find the equation in slope-intercept form,of the line containing the point (2,-1) and perpendicular to the line 3x+2y-8=0
find the equation in slope-intercept form,of the line containing the point (2,-1) and perpendicular to the line 3x+2y-8=0
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,116 Sep 29, 2009 #2 tmac324 said: find the equation in slope-intercept form,of the line containing the point (2,-1) and perpendicular to the line 3x+2y-8=0 Click to expand... Here's a hint: perpendicular lines have slopes that are OPPOSITE RECIPROCALS. So...start by finding the slope of the given line, 3x + 2y - 8 = 0 Then, the slope of the line you're looking for is the opposite reciprocal of the slope of the given line. Show us what you've gotten up to this point, and we can take it further.
tmac324 said: find the equation in slope-intercept form,of the line containing the point (2,-1) and perpendicular to the line 3x+2y-8=0 Click to expand... Here's a hint: perpendicular lines have slopes that are OPPOSITE RECIPROCALS. So...start by finding the slope of the given line, 3x + 2y - 8 = 0 Then, the slope of the line you're looking for is the opposite reciprocal of the slope of the given line. Show us what you've gotten up to this point, and we can take it further.
