L lmj89 New member Joined Sep 30, 2008 Messages 1 Sep 30, 2008 #1 square root of 3 over square root of 2 + square root of 2 over square root of 3; I think the answer would be 5/6 but I'm not sure!
square root of 3 over square root of 2 + square root of 2 over square root of 3; I think the answer would be 5/6 but I'm not sure!
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Sep 30, 2008 #2 Use more parentheses. Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2}}+\frac{\sqrt{2}}{\sqrt{3}}\) Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2} + \frac{\sqrt{2}}{\sqrt{3}}}\) Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2+\frac{\sqrt{2}}{\sqrt{3}}}}\) Learning to communicate IS part of the process. Good first try, now let's see if we can't step it up a bit.
Use more parentheses. Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2}}+\frac{\sqrt{2}}{\sqrt{3}}\) Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2} + \frac{\sqrt{2}}{\sqrt{3}}}\) Do you mean this: \(\displaystyle \frac{\sqrt{3}}{\sqrt{2+\frac{\sqrt{2}}{\sqrt{3}}}}\) Learning to communicate IS part of the process. Good first try, now let's see if we can't step it up a bit.
L Loren Senior Member Joined Aug 28, 2007 Messages 1,298 Sep 30, 2008 #3 Doesn't \(\displaystyle \sqrt2 \cdot \sqrt3 = \sqrt6\) ?