H hobdenas New member Joined Sep 25, 2005 Messages 12 Sep 25, 2005 #1 The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle?
The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle?
A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 847 Sep 25, 2005 #2 2l+2w= 14.9 w is width l is length but l=1.9+w substitute 2[1.9+w+w]=14.9 3.8 +4w= 14.9 4w= 11.1 w=11.1/4 Arthur
2l+2w= 14.9 w is width l is length but l=1.9+w substitute 2[1.9+w+w]=14.9 3.8 +4w= 14.9 4w= 11.1 w=11.1/4 Arthur
P Peachyyy New member Joined May 27, 2005 Messages 15 Sep 25, 2005 #3 hobdenas said: The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle? Click to expand... Perimeter is the total distance around the rectangle. Let x be the width that would make the length x + 1.9 Can you take it from there?
hobdenas said: The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle? Click to expand... Perimeter is the total distance around the rectangle. Let x be the width that would make the length x + 1.9 Can you take it from there?
