help solving a implicit differientation

[grapz]

(x^4 + y^4 )^1/2 = x^2 + y


so i do take the derviative of both sides.
and i get

1/2 ( x^ 4 + y^4) ^-1/2 ( 4x^3 + 4y^3(dy/dx) = 2x + dy/dx

However i am stuck and can not isolate for dy/dx

can some1 help me thanks

 

[tkhunny]

(x^4 + y^4 )^1/2 = x^2 + y
1/2 ( x^ 4 + y^4) ^-1/2 ( 4x^3 + 4y^3(dy/dx) = 2x + dy/dx

You waded through that mess only to drown in the algebra? It's a shame.

What, besides the missing parenthesis, is troubling you.

(1/2 ( x^ 4 + y^4) ^-1/2) [ 4x^3 + 4y^3(dy/dx)] = 2x + dy/dx

Sometimes, I like to simplify a bit so I can see more clearly. Can you solve this?

(Mess) [ 4x^3 + 4y^3(dy/dx)] = 2x + dy/dx

(Mess)*4x^3 + Mess*4y^3(dy/dx)] = 2x + dy/dx

(Mess)*4x^3 - 2x = dy/dx - Mess*4y^3(dy/dx)

(Mess)*4x^3 - 2x = dy/dx(1 - Mess*4y^3)

[(Mess)*4x^3 - 2x]/[1 - Mess*4y^3] = dy/dx

Now what?