O oilrip New member Joined Jun 11, 2013 Messages 1 Jun 11, 2013 #1 Hi.. can anyone help me to solve the following question. find dy/dx by differentiating implicitly. When applicable, express the result in terms of x and y. 3x2/(y2+1) + y = 3x + 1 Thanks in advance..
Hi.. can anyone help me to solve the following question. find dy/dx by differentiating implicitly. When applicable, express the result in terms of x and y. 3x2/(y2+1) + y = 3x + 1 Thanks in advance..
D DrPhil Senior Member Joined Nov 29, 2012 Messages 1,383 Jun 11, 2013 #2 oilrip said: Hi.. can anyone help me to solve the following question. find dy/dx by differentiating implicitly. When applicable, express the result in terms of x and y. 3x2/(y2+1) + y = 3x + 1 Thanks in advance.. Click to expand... Since (y^2 + 1) is never zero, it is valid to multiply all terms by it: \(\displaystyle 3x^2 + y (y^2 - 1) = 3x (y^2 - 1) + 1(y^2 - 1)\) Does that help? If you need more hints, Show us your work! (So we know where you are getting stuck.)
oilrip said: Hi.. can anyone help me to solve the following question. find dy/dx by differentiating implicitly. When applicable, express the result in terms of x and y. 3x2/(y2+1) + y = 3x + 1 Thanks in advance.. Click to expand... Since (y^2 + 1) is never zero, it is valid to multiply all terms by it: \(\displaystyle 3x^2 + y (y^2 - 1) = 3x (y^2 - 1) + 1(y^2 - 1)\) Does that help? If you need more hints, Show us your work! (So we know where you are getting stuck.)