help with dominatos

[seppege]

I have to simplify this, but I can't figure out how to start. I've tried putting a-b to the same dom as in the second term: (b-a) .Any help with some explenation would be appreciated. One of the four awsers is correct.

 

[Deleted member 4993]

I have to simplify this, but I can't figure out how to start. I've tried putting a-b to the same dom as in the second term: (b-a) .Any help with some explenation would be appreciated. One of the four awsers is correct. View attachment 22353

\(\displaystyle \frac{a}{a-b} + \frac{ab}{(b-a)^2}\)

\(\displaystyle = \ \frac{a}{a-b} + \frac{ab}{(a-b)^2}\)

\(\displaystyle = \ \frac{a(a-b) \ + \ ab}{(a-b)^2}\)

continue......

Please show us what you have tried and exactly where you are stuck.

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[seppege]

Thus is what I've tried earlier

 

[pka]

Thus is what I've tried earlier

You are making it far too complicated.
First \(\large\bf(b-a)^2=(a-b)^2\) so that
\(\dfrac{a}{a-b}+\dfrac{ab}{(a-b)^2}\\\dfrac{a^2-ab+ab}{(a-b)^2}\\\dfrac{a^2}{(b-a)^2}\).