9n2+30n+25
M masters Full Member Joined Mar 30, 2007 Messages 378 Feb 24, 2010 #2 katielauren228 said: 9n2+30n+25 Click to expand... Hi katielauren, I assume you need to factor this expression. Notice that the first and third terms are perfect squares. 9n2+30n+25=(3n+5)(3n+5)=(3n+5)2\displaystyle 9n^2+30n+25=(3n+5)(3n+5)=(3n+5)^29n2+30n+25=(3n+5)(3n+5)=(3n+5)2 This is a perfect square trinomial in the form: (a+b)2=a2+2ab+b2\displaystyle (a+b)^2=a^2+2ab+b^2(a+b)2=a2+2ab+b2
katielauren228 said: 9n2+30n+25 Click to expand... Hi katielauren, I assume you need to factor this expression. Notice that the first and third terms are perfect squares. 9n2+30n+25=(3n+5)(3n+5)=(3n+5)2\displaystyle 9n^2+30n+25=(3n+5)(3n+5)=(3n+5)^29n2+30n+25=(3n+5)(3n+5)=(3n+5)2 This is a perfect square trinomial in the form: (a+b)2=a2+2ab+b2\displaystyle (a+b)^2=a^2+2ab+b^2(a+b)2=a2+2ab+b2
