Can someone please let me know if I'm on the right track with this question -
A bag contains 4 white, 6 yellow, 5 blue, and 7 red balls. If a set of 4 balls is randomly selected, what is the probability that each of the balls will be
(a) of the same color if drawn with no replacement.
(b) of different color if drawn with no replacement.
For (a), I'm doing -
P(wwww) = 4/22 * 3/21 * 2/20 * 1/19
P(yyyy) = 6/22 * 5/21 * 4/20 * 3/19
P(bbbb) = 5/22* 4/21* 3/20* 2/19
P(rrrr) = 6/22 * 5/21 * 4/20 * 3/19
Then adding up the 4 probabilities above
For (b), I'm doing -
P(w) = 4/22
P(y) = 6/21
P(b) = 5/20
P(r) = 7/19
Then also adding up the 4 probabilities
A bag contains 4 white, 6 yellow, 5 blue, and 7 red balls. If a set of 4 balls is randomly selected, what is the probability that each of the balls will be
(a) of the same color if drawn with no replacement.
(b) of different color if drawn with no replacement.
For (a), I'm doing -
P(wwww) = 4/22 * 3/21 * 2/20 * 1/19
P(yyyy) = 6/22 * 5/21 * 4/20 * 3/19
P(bbbb) = 5/22* 4/21* 3/20* 2/19
P(rrrr) = 6/22 * 5/21 * 4/20 * 3/19
Then adding up the 4 probabilities above
For (b), I'm doing -
P(w) = 4/22
P(y) = 6/21
P(b) = 5/20
P(r) = 7/19
Then also adding up the 4 probabilities