MAZambelli4353
New member
- Joined
- Feb 22, 2016
- Messages
- 1
y=4x-x^2, y=3, about x=1
you dont need to solve the whole thing, just give me my h(x) and r(x).[FONT=Helvetica Neue, Helvetica, Arial, sans-serif]I have h(x)=3-(4x-x^2) and r(x)=1-x. Is that right? Im doing the shaded region above the curve, right? Usually they give you the bounds but this time they dont completely so do they assume to go between [0,1]? I keep getting the wrong answer. the right answer is 8pi/3.[/FONT]
you dont need to solve the whole thing, just give me my h(x) and r(x).[FONT=Helvetica Neue, Helvetica, Arial, sans-serif]I have h(x)=3-(4x-x^2) and r(x)=1-x. Is that right? Im doing the shaded region above the curve, right? Usually they give you the bounds but this time they dont completely so do they assume to go between [0,1]? I keep getting the wrong answer. the right answer is 8pi/3.[/FONT]