T tsj1114 New member Joined Jan 9, 2017 Messages 8 Jan 9, 2017 #1 The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find lim x/ t t-->0
The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find lim x/ t t-->0
Harry_the_cat Elite Member Joined Mar 16, 2016 Messages 3,779 Jan 9, 2017 #2 tsj1114 said: The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find lim x/ t t-->0 Click to expand... lim x/ t = dx/dt. So the question is asking you to find dx/dt. t-->0
tsj1114 said: The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find lim x/ t t-->0 Click to expand... lim x/ t = dx/dt. So the question is asking you to find dx/dt. t-->0
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Jan 11, 2017 #3 tsj1114 said: The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find \(\displaystyle \,\displaystyle \lim_{\Delta t \rightarrow 0}\, \dfrac{\Delta x}{\Delta t}\) Click to expand... How does your book define the "delta" operator? What did you get when you plugged the expression for x into this definition? Please reply showing all of your steps so far. Thank you!
tsj1114 said: The x-coordinate of a particle moving along the x-axis at time t is time given by x=e^(3t). Find \(\displaystyle \,\displaystyle \lim_{\Delta t \rightarrow 0}\, \dfrac{\Delta x}{\Delta t}\) Click to expand... How does your book define the "delta" operator? What did you get when you plugged the expression for x into this definition? Please reply showing all of your steps so far. Thank you!