Help with Tangent Lines with Derivative Rules

[sekcb]

Let f be a differentiable function with f(-3)=5 and f'(-3)=3 Let the function g(x)=(x-1)f(x) Write the equation of the line tangent to the graph of g at the point where x=-3

 

[Steven G]

To receive help on this forum you need to state where you are stuck and to show us your work.

Here is a hint:

g'(x) = f(x) + (x-1)f'(x) by the product rule.

What is one point on g that you know? What is the slope at that point?