How do I evaluate for T?

[aresyl]

This says this is solvable but I don't understand what to do.

 

[blamocur]

What is 'R' in your expression ?

 

[aresyl]

What is 'R' in your expression ?

it's a unit for temperature

 

[topsquark]

A quick Mr. Science moment: R is the unit for a temperature measured in the Rankine scale, which is similar to the Kelvin scale, but measured in Fahrenheit degrees.

-Dan

 

[topsquark]

This says this is solvable but I don't understand what to do.

This can only be solved numerically or, more easily, graphically.

-Dan

 

[blamocur]

A quick Mr. Science moment: R is the unit for a temperature measured in the Rankine scale, which is similar to the Kelvin scale, but measured in Fahrenheit degrees.

-Dan

Thanks. My next silly question: what does [imath]R^{-1}[/imath] in the left hand side mean ?

 

[Dr.Peterson]

This says this is solvable but I don't understand what to do.

It doesn't say it can be solved algebraically, only that they solved it by some means, probably by technology. What is the context? Do they say anything more about what tools they used?

Here is a graph (in Desmos) of the two sides of the equation, showing the solution:



One thing you can see is that your source rounded the solution to the nearest degree.

Thanks. My next silly question: what does [imath]R^{-1}[/imath] in the left hand side mean ?

It means "per degree Rankine", which is consistent with the RHS. (In the RHS, the constant must have units of degree Rankine to cancel the other terms.)