I've been stuck on this equation for a while now and I need it to continue on with my question; how am I supposed to solve for:
f(x) = 2 in -2cos(3x)+1=2
I know that it'll eventually turn out to be; cos(3x) = -1/2 but what should I do after this?
f(x) = 2 in -2cos(3x)+1=2
I know that it'll eventually turn out to be; cos(3x) = -1/2 but what should I do after this?