Agent Smith
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- Oct 18, 2023
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y=xx1?
My knowledge of differential calculus is limited to ... for y=axn, dxdy=naxn−1
My knowledge of differential calculus is limited to ... for y=axn, dxdy=naxn−1
What about lny=x1lnx and use implicity differentiation?y=xx1?
My knowledge of differential calculus is limited to ... for y=axn, dxdy=naxn−1
I don't see the connection. I'm on the 2nd chapter of an introductory book on calculus and that's about all I know.What about lny=x1lnx and use implicity differentiation?
I doubt it if you'll be interested in the original problem. I was exploring sets and I found out that for a set A, whose cardinality n(A) = p, the power set of the set A, P(A) has a cardinality n(P(A)) = 2pThe suggestion was to use logarithmic differentiation; look it up in your book. Unfortunately, it is probably considerably later than where you are.
Please show us an image of the problem, and the title of the chapter, so we can confirm what you might be expected to do. This can't really be done without the more advanced methods, so I suspect they are asking for something other than what you think..
You do not have to do it like this. You can do it directly.So If u=lny=x1lnx then I know that dxdu=dydu×dxdy
u is a function of y is a function of x
This is from last night's reading session.
Exactly. Did you expect to get that?So for f(x)=xx1, we have f′(x). At maxima, f′(x)=0 and x=e?![]()
What you're saying is that this is not a problem from the book you say you're reading. That explains why it would require more than you've learned yet. That's all we need to know about the origin of your question.I doubt it if you'll be interested in the original problem. I was exploring sets
Yes, that's what you'll get.So for f(x)=xx1, we have f′(x). At maxima, f′(x)=0 and x=e?![]()